БУРМАСТЕР PRO · ENFluids and hydraulics: models and interpretation
Distinguish fluid properties, hydrostatics, annular losses and geometrical flow velocity.
Prerequisites: Density, pressure, circular area, TVD and unit conversion.
Original learning material. Independent domain and translation reviews are pending. Not accredited training, an operating instruction or work authorisation.
Open interactive studyCHAPTER 1Fluid properties and measurement conditions
Density, rheological response and filtration answer different questions. Density relates mass to volume and enters the hydrostatic model. Rheology describes the flow-deformation/stress relationship under defined conditions. Filtration concerns movement of a liquid phase through a specified medium using a chosen method. One number cannot replace the full property set.
Before comparing measurements, check units, temperature, sampling location/time, sample preparation, method and instrument condition. A change may reflect a real fluid change, sample composition or non-comparable methods. Without this context, arithmetic difference remains a difference between records rather than an established hydraulic cause.
Build a measurement passport: quantity, value, unit, conditions, method, source, uncertainty and operational context. Mark missing information explicitly. A constant-density learning model does not claim uniform density throughout the well: temperature, pressure, gas and solids can change conditions. Fluid formulation and treatment require a separate programme and a competent specialist.
Walkthrough
1.20 and 1.25 g/cm³ correspond to 1200 and 1250 kg/m³. The difference is 50 kg/m³. At a fictional 1000 m TVD it changes ρgH by 0.4905 MPa if other assumptions remain fixed.
Independent task
Compare 1.18 g/cm³ and 1210 kg/m³. Find the difference and its hydrostatic contribution at 800 m TVD. Which measurement conditions must be comparable?
Reveal debrief and criteria
1180 and 1210 kg/m³; Δρ = 30 kg/m³; ΔP = 30 × 9.81 × 800 / 10⁶ = 0.23544 MPa. Sampling context, temperature, method and sample comparability are needed; treatment is not determined.
- Units agree
- difference has a sign and baseline
- effect is computed within the model
- properties are not treated as interchangeable.
Editorial criteria; independent assessment and learning-outcome validation are pending.
Attempt in the interactive worksheet →
CHAPTER 2Composite columns and point-specific ECD
For a constant-density column, the hydrostatic contribution is ρgH. A vertically segmented column uses the sum gΣρiHi. Heights must be vertical and share a reference datum. Along-hole lengths alone may be insufficient for this sum in a deviated well.
During circulation, relevant flow-path losses contribute to pressure at the selected point. The learning model ECD = ρ + ΔPann/(gH) requires consistent units. Here ΔPann is annular loss above that point. Total standpipe pressure includes other loop components and is not an automatic substitute.
Always state point and condition: bottomhole or shoe, static or circulating, density/conditions and surface pressure reference. Subtracting values with different datums does not give a valid pressure margin. The model excludes pipe-motion transients, multiphase effects and compressibility. It does not establish an operating pressure window or field setpoints without design evidence.
Walkthrough
500 m at 1000 kg/m³ plus 500 m at 1200 kg/m³ gives P = 9.81(500000+600000)/10⁶ = 10.791 MPa. In a separate uniform-column example at 1200 kg/m³, H = 1000 m and ΔPann = 0.981 MPa, ECD is 1300 kg/m³. Do not combine the two examples as one column.
Independent task
A uniform learning column has density 1150 kg/m³, H = 1500 m and annular loss 1.4715 MPa. Find hydrostatics, the circulating value on the same reference and ECD.
Reveal debrief and criteria
Hydrostatics: 16.92225 MPa; including stated loss: 18.39375 MPa; density increment: 100 kg/m³; ECD: 1250 kg/m³. These are model results, not safe operating limits.
- Point and TVD are stated
- Pa/MPa are consistent
- annular loss is selected
- no field setpoint is inferred.
Editorial criteria; independent assessment and learning-outcome validation are pending.
Attempt in the interactive worksheet →
CHAPTER 3Annular flow, volume and ideal transit time
Geometrical average velocity in a constant annular section is v = Q/A. For concentric cylinders, A = π(D²−d²)/4, where D is the outer boundary inside diameter and d the inner pipe outside diameter. Pipe ID is not appropriate here. Varying sections require interval calculations.
An ideal volume transit time through a constant segment is t = V/Q. This kinematic model excludes particle slip, velocity distribution, mixing, stagnant regions and cuttings transport. Equal average velocity does not establish equal hole-cleaning effectiveness.
Use the result to check dimensions and magnitude. A smaller area gives higher average velocity at fixed flow, but this is not a recommendation to narrow clearance or raise flow. Real losses, equipment constraints and rock interaction also change. Before comparing with an observed response time, clarify whole-path volume, sensor location, measurement delay and transient conditions.
Walkthrough
D = 0.216 m and d = 0.127 m give A ≈ 0.02397584 m². At Q = 0.020 m³/s, average velocity is ≈0.83417 m/s. For L = 100 m, volume is ≈2.39758 m³ and ideal time ≈119.879 s.
Independent task
A fictional segment has A = 0.025 m², L = 200 m and Q = 25 L/s. Find volume, average velocity and ideal time. Name three excluded effects.
Reveal debrief and criteria
V = 5 m³; Q = 0.025 m³/s; v = 1 m/s; t = 200 s. Exclusions include particle slip, mixing and varying geometry. The number does not establish hole cleaning.
- Flow units are converted
- area and volume are distinguished
- t agrees with L/v
- transport-model limitations are stated.
Editorial criteria; independent assessment and learning-outcome validation are pending.
Attempt in the interactive worksheet →
CAPSTONECapstone: a hydraulic model note
A fictional uniform column has density 1200 kg/m³, TVD 1000 m and annular loss 0.981 MPa. A separate constant annular segment has area 0.025 m² and length 100 m; flow is 20 L/s. A draft substitutes total standpipe pressure for annular loss and calls V/Q proven cuttings-return time.
Align units and explain why neither substitution is supported. Pressure and kinematic transit time belong to different models. Showing them together does not establish actual cleaning or operating suitability.
Walkthrough
Write the hydrostatic, circulating and geometrical parts separately.
Independent task
Find hydrostatics, ECD, segment volume, average velocity and ideal time. Correct both unsupported conclusions.
Reveal debrief and criteria
Hydrostatics are 11.772 MPa; ECD 1300 kg/m³; volume 2.5 m³; velocity 0.8 m/s; ideal time 125 s. Standpipe pressure is not the specified annular loss, and V/Q does not model particle slip or transport. No actual operating state is prescribed.
- Five results have units
- model boundaries are separated
- both substitutions are explained
- no operating recommendation is made.
Editorial criteria; independent assessment and learning-outcome validation are pending.
Attempt in the interactive worksheet →